Home
Class 11
CHEMISTRY
20mL, 0.1N acetic acid is mixed with 10m...

`20mL`, `0.1N` acetic acid is mixed with `10mL` `0.1N` solution of `NaOH`. The pH of the resulting solution is (`pK_(a)` of acetic acid is `4.74`)
`3.74`
`4.74`
`5.74`
`6.74`

Promotional Banner

Similar Questions

Explore conceptually related problems

100 ml of 0.1 N NaOH is mixed with 50 ml of 0.1 N H_2SO_4 . The pH of the resulting solution is

When 0.2M solution of acetic acid is neutralised with 0.2M NaOH in 500 mL of water, the pH of the resulting solution will be: [pK_(a) of acetic acid = 4.74]

Calculate the pH of 0.05M sodium acetate solution, if the pK_(a) of acetic acid is 4.74 .

20 mL of 0.1N HCI is mixed with 20 ml of 0.1N KOH . The pH of the solution would be

If 20 mL of 0.1 M NaOH is added to 30 mL of 0.2 M CH_(3)COOH (pK_(a)=4.74) , the pH of the resulting solution is :

40mL sample of 0.1M solution of nitric acid is added to 20mL of 0.3M aqueous ammonia. What is the pH of the resulting solution? (pK_b = 4.7447)

50 mL of 2N acetic acid mixed with 10 mL of 1N sodium acetate solution will have an approximate pH of (K_(a)=10^(-5)) :

10 mL of 1 NHCl is mixed with 20 mL of 1 MH_(2)SO_(4) and 30 mL of 1M NaOH. The resultant solution has:

40 ml of 0.1 M ammonia is mixed with 20 ml of 0.1 M HCl . What is the pH of the mixture ? ( pK_(b) of ammonia solution is 4.74. )

10mL of a strong acid solution of pH=2.000 are mixed with 990 mL of another strong acid solution of pH=4.000 . The pH of the resulting solution will be :