One often comes across the following kind of statement concerning circular motion : 'A particle moving uniformly along a circle experience a force directed towards the centre (centripetal force) and an equal and opposite force directed away from the centre (centrifugal force). The two forces together keep the particel in equilibrium'. Explain, what is wrong with this statement.

One end of a string of length t is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is : T is the tension in the string. [Choose the correct alternative].

State whether the following statement is true or false-"When a person walks on a rough surface,the frictional force exerted by the surface on the person is opposite to the direction of his motion".

A wheel in uniform motion about an axis passing through its centre and perpendicular to its plane is considered to be in mechanical (translational plus rotational equilibrium because no net external force or torque is required to sustain its motion. However, the particles that constitute the wheel do experience a centripetal acceleration directed towards the centre. How do you reconcile this fact with the wheel being in equilibrium? How would you set a half - wheel into uniform motion about an axis passing through the centre of mass of the wheel and perpendicular to its plane? Wil you require external forces to sustain the motion?

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . When a charged particle q is moving with velocity vecv in a magnetic field vecB , the force is non-zero. It means.

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . Under the influenece of a uniform magnetic field, a charged particles is moving in a circle of radius r with speed v. The time period of motion.

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . The time period of a charged particle undergoing a circular motion in uniform magnetic field is independent of its

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . If an electron and a proton having same momenta enter perpendicular to a magnetic field, then

Direction. In the follwing questions, a statement of assertion is followed by a statement of reason. While answering a question, you are required to choose the correct are out of the given four responses and mark it as (A). If both assertion and reason are true and reason is the correct explanation of the assertion, (B) if both assertion and reason are true but reason is not correct explanation of the assertion. (C) if asssertion is true, but reason if false, (D) if both assertion and reason are false Assertion : The energy of a charged particle does not change, when it moves inside the magnetic field. Reason: It is because, force on the charged particle due to the magnetic field acts perpendicular to its path.

A particle is in linear simple harmonic motion between two points, A and B, 10 cm apart. Take the direction from A to B as the positive direction and give the signs of velocity, acceleration and force on the particle when it is at 2 cm away from B going towards A,

A particle is in linear simple harmonic motion between two points, A and B, 10 cm apart. Take the direction from A to B as the positive direction and give the signs of velocity, acceleration and force on the particle when it is at 3 cm away from A going towards B, and