When a force of constant magnitude always acts perpendicular to the motion of a particle then:

The force of friction on a moving object always acts:

If the acceleration of the particle is constant in magnitude but ot in direction, what type of path does the particle follow?

Why are particles of a matter always in motion ?

When a charged particle moves perpendicular to a magnetic field, then

Discuss the motion of a charged particle when subjected to a uniform magnetic field when The direction of motion of charged particle is perpendicular to the magnetic field?

Two particles of equal masses m and m are connected by a light string of length 2l. A constant force F is applied continuously at the mid-point of the string, always along the perpendicular bisector of the straight line joining the two particles. Show that when the distance between the two particles is x, the acceleration of the particle is a = F/m = (x)/((1^2 - x^2) ^(1//2)

If the resultant of two forces is equal in magnitude to one of the components and perpendicular to it direction, find the other components using the vector method.

A paticle of mass m is executing uniform circular motion on a path of radius r. If p is the magnitude of its linear momentum, then the radial force acting on the particle is

A particle is actedsimultaneously by mutually perpendicular simple hormonic motions x = a cos 1omegat and y = a sin omegat . The trajectory of motion of the particle will be

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . When a charged particle q is moving with velocity vecv in a magnetic field vecB , the force is non-zero. It means.