An automobile is moving on a horizontal road with a speed `v`. If the coefficient of friction between the tyres and the road is `mu`, show that the shortest distance in which the automobile can be stopped in `v^2//2mug`.

Options

A. `v/(2 mu g)`
B. `(v^2)/(2 mu g)`
C. `((v^2)/(2 mu g))^(1//2)`
D. `((v^2)/(2 mu g))^2`