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If sectheta+tantheta=x , then tantheta= ...

If `sectheta+tantheta=x` , then `tantheta=` `(x^2+1)/x` (b) `(x^2-1)/x` (c) `(x^2+1)/(2x)` (d) `(x^2-1)/(2x)`

A

`2/x`

B

`1/2x`

C

`(x^2-1)/(2x)`

D

`(2x)/(x^2-1)`

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The correct Answer is:
C
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