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Find the quadratic polynomial, whose zer...

Find the quadratic polynomial, whose zeroes are -3 and 4.

A

`x^2-x-12`

B

`2x^2-x+12`

C

`x^2-x+4`

D

`x^2-3x+4`

Text Solution

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The correct Answer is:
To find the quadratic polynomial whose zeroes are -3 and 4, we can follow these steps: ### Step 1: Identify the zeroes The given zeroes are: - α = -3 - β = 4 ### Step 2: Write the polynomial in factored form A quadratic polynomial can be expressed in the factored form as: \[ f(x) = (x - α)(x - β) \] Substituting the values of α and β, we have: \[ f(x) = (x - (-3))(x - 4) \] This simplifies to: \[ f(x) = (x + 3)(x - 4) \] ### Step 3: Expand the polynomial Now, we will expand the expression: \[ f(x) = (x + 3)(x - 4) \] Using the distributive property (also known as the FOIL method for binomials): \[ f(x) = x^2 - 4x + 3x - 12 \] ### Step 4: Combine like terms Now, combine the like terms: \[ f(x) = x^2 - 4x + 3x - 12 \] \[ f(x) = x^2 - x - 12 \] ### Step 5: Final polynomial Thus, the quadratic polynomial whose zeroes are -3 and 4 is: \[ f(x) = x^2 - x - 12 \] ---
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