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A vertical pole of length 6 m casts a sh...

A vertical pole of length 6 m casts a shadow 4 m long on the ground at the same time a tower casts a shadow 28 m long what is the height of the tower?

A

45 cm

B

36 cm

C

42 cm

D

64 cm

Text Solution

AI Generated Solution

The correct Answer is:
To find the height of the tower based on the given information, we can use the concept of similar triangles. Here’s a step-by-step solution: ### Step 1: Understand the Problem We have a vertical pole of height 6 m that casts a shadow of 4 m. At the same time, a tower casts a shadow of 28 m. We need to find the height of the tower. ### Step 2: Set Up the Ratios Since the sun’s rays create similar triangles, we can set up the following ratio based on the heights and shadows: \[ \frac{\text{Height of Pole}}{\text{Length of Pole's Shadow}} = \frac{\text{Height of Tower}}{\text{Length of Tower's Shadow}} \] Substituting the known values: \[ \frac{6 \text{ m}}{4 \text{ m}} = \frac{h}{28 \text{ m}} \] where \( h \) is the height of the tower. ### Step 3: Cross-Multiply to Solve for \( h \) Cross-multiplying gives us: \[ 6 \text{ m} \times 28 \text{ m} = 4 \text{ m} \times h \] Calculating the left side: \[ 168 \text{ m}^2 = 4 \text{ m} \times h \] ### Step 4: Isolate \( h \) Now, divide both sides by 4 m to solve for \( h \): \[ h = \frac{168 \text{ m}^2}{4 \text{ m}} = 42 \text{ m} \] ### Conclusion The height of the tower is \( 42 \text{ m} \). ---
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