Refractive index of ethanol is 1.361 and it is known that benzene is optically dense that ethanol. Which could be the refractive index of benzene:

Options

A. 1.35
B. 1.281
C. 1.333
D. `1.501`

Answer

To solve the problem, we need to determine the possible refractive index of benzene given that it is optically denser than ethanol, which has a refractive index of 1.361.

### Step-by-Step Solution:

1. **Understand the Concept of Refractive Index**:
The refractive index (µ) of a medium indicates how much light slows down when it enters that medium. A higher refractive index means the medium is optically denser.

2. **Identify the Given Information**:
- Refractive index of ethanol (µ_E) = 1.361
- Benzene is optically denser than ethanol.

3. **Establish the Relationship**:
Since benzene is optically denser than ethanol, its refractive index (µ_B) must be greater than that of ethanol:
\[ µ_B > µ_E \]
Therefore:
\[ µ_B > 1.361 \]

4. **Evaluate the Options**:
You need to check the options provided for the refractive index of benzene and see which one is greater than 1.361.

- **Option 1**: µ_B = 1.35 (This is less than 1.361, so it is incorrect)
- **Option 2**: µ_B = 1.281 (This is also less than 1.361, so it is incorrect)
- **Option 3**: µ_B = 1.33 (This is still less than 1.361, so it is incorrect)
- **Option 4**: µ_B = 1.501 (This is greater than 1.361, so it is correct)

5. **Conclusion**:
The only option that satisfies the condition of being optically denser than ethanol is:
\[ \text{Refractive index of benzene (µ_B)} = 1.501 \]

### Final Answer:
The refractive index of benzene could be 1.501.

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