When 2 moles of `Na_(2)CO_(3)` reacts with 6 moles of HCl the volume of `CO_(2)` gas liberated at S.T.P will be (A) 22.4L (B) 44.8L (C) 67.4L (D) 89.6L

At NTP, 1L of O_2 reacts with 3L of carbon monoxide. What will be the volume of CO and CO_2 after the reaction?

When 22.4 L of H_(2)(g) is mixed with 11.2 L of Cl_(2)(g) , each at STP, the moles of HCl(g) formed is equal to

A balanced equation for combustion of methane is given below: CH_(4(g)) + 2O_(2(g)) to CO_(2(g)) + 2H_2O_(g) Which of the following statements is not correct on the basis of the above chemical equation? (A) one mole of CH4 reacts with 2 moles of oxygen to give one mole of CO2 (B) one molecule of CH4 reacts with 2 molecules of oxygen to give one molecule of CO2 and 2 molecules of water (C) 22.4L methane reacts with 44.8L of oxygen to give 44.8L of CO2 and 22.4L of water (D) 16g of methane reacts with 64g of O2 to give 44g of CO2 and 36g of water

At STP 10 L of H_(2)S was reacted with 10 L of SO_(2) . The volume of gas remaining after the reaction is complete would be

The volume of 2.89 g of carbon monoxide at 27^(@)C and 0.821 atm pressure is (A) 2.5 L (B) 4 L (C) 3.5 L (D) 3 L

Calculate the volume occupied at S.T.P. by 2 moles of CO_(2)

The pressure of 2 mole of ideal gas at 546 K having volume 44.8 L is

8g of O_(2) gas at S.T.P. is expanded so that volume is doubled. Calculate work in atm L

Weight of CO_(2) in a 10 L cylinder at 5 atm and 27 .^(@)C is (A)200 g (B)224 g (c)44 g (d) 89.3 g

On carrying out the electrolysis of acidified water, the volume of hydrogen liberated at STP condition is 22.4L . The volume of oxygen liberated is a.22.4 L b.44.8 L c.11.2 L d.2.24 L