Rationalize :
( a ) `1/sqrt(7)`
( b ) `1/( sqrt7 - sqrt6 )`

(1)/(sqrt(7)-sqrt(6))

1/(sqrt7+sqrt6-sqrt13)=

Rationalise the denominators of the following (a) 1/(3+sqrt2) (b) 1/(sqrt7-sqrt6)

Rationalise the denominators of the following : (i) (1)/(sqrt(7)) (ii) (1)/(sqrt(7)-sqrt(6)) (iii) (1)/(sqrt(5)+sqrt(2)) (iv) (1)/(sqrt(7)-2)

Rationalise the denominators of the following: (i) 1/(sqrt(7)) (ii) 1/(sqrt(7)-sqrt(6)) (iii) 1/(sqrt(5)+sqrt(2)) (iv) 1/(sqrt(7)-2)

Rationalize 3/(2sqrt7+sqrt5)

(3+sqrt(7))/(3-sqrt(7))=a+b sqrt(7)

What is the value of (1/(sqrt(9) - sqrt(8)) - 1/(sqrt(8) - sqrt(7)) + 1/(sqrt(7) - sqrt(6)) - 1/(sqrt(6) - sqrt(5)) + 1/(sqrt(5) - sqrt(4))) ?

The value of (1)/( sqrt(7) - sqrt(6)) - (1)/( sqrt(6) - sqrt(5) ) +(1)/( sqrt(5) -2) - (1)/( sqrt(8) - sqrt(7) ) +(1)/( 3- sqrt(8)) is

Rationalise the denominator of (sqrt(7)-sqrt(6))/(sqrt(7)+sqrt(6))