7th Mathematics Term-1 real paper 9 December 2021 | PSEB Term-1 exam Maths | GAURAV CROOKS 7th #pseb

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4th term of an A.P. is equal to 3 times its first term and 7th term exceeds twice the 3rd term by 1. Find the first term and the common difference.

Determine the arithmetic progression whose 3rd term is 5 and 7th term is 9.

The sum of the 2nd term and the 7th term of an A.P. is 30. If its 15th term is 1 less than twice of its 8th term, find the A.P.

In ( 2^(1/3)+1/3^(1/ 3))^n if the ratio of 7th term from the beginning to the 7th term from the end is 1/6, then find the value of ndot

If the ratio of the 7th term from the beginning to the 7th term from the end in the expansion of (sqrt2+(1)/(sqrt3))^x is 1/6 , then x is

In (3 3+1/(3 3))^n if the ratio of 7th term from the beginning to the 7th term from the end is 1/6, then find the value of ndot

In (2^(1/3)+1/(3^(1/3)))^n if the ratio of 7th term from the beginning to the 7th term from the end is 1/6 , then the value of n is (a) 6 (b) 9 (c) 12 (d) 15

If 7 times the 7th term of an A.P. is equal to 11 times its 11th term, show that the 18th term of the A.P. is zero.