Differential equation `dy/dx +1/x sin2y =x^3cos^2y`
is represented by a family of curves which is given by

The general solution of the differential equation dy/dx = (1-x)/y is a family of curves which look like which of the following :

Solve the differential equation: (dy)/(dx)+2y=sin x

The differential equation (dy)/(dx)+x sin 2y=x^(3)cos^(2)y when transformed to linear form becomes

Solve the differential equation: (dy)/(dx)+2y=sin\ 3x

Solution of differential equation (dy)/(dx)=sin(x+y)+cos(x+y) is

Form the differential equation of the family of curves represented by y^2=(x-c)^3 .

Form a differential equation representing the given family of curves by eliminating arbitrary constants a and b.y = ex (a cos x + b sin x)

The curve satisfying the differential equation (dx)/(dy) = (x + 2yx^2)/(y-2x^3) and passing through (1, 0) is given by

Solve the differential equation: x \ cos^2y\ dx=y \ cos^2x\ dy

Form the differential equation representing the family of curves y^2-2ay+x^2=a^2 , where a is an arbitrary constant.