The equivalent mass of metal is E and its formula of oxide is `M_(n)O_(m)` .The atomic mass of the metal is

A metal M of equivalent mass E forms an oxide of molecular formula M_(x)O_(y) The atomic mass of the metal is given by the correct equation .

The equivalent weight of a metal is 9 and vapour density of its chloride is 59.25. The atomic weight of metal is :

The equivalent mass of a metal is twice to that of oxygen. How many times is the equivalent mass of it's oxide than the equivalent mass of the metal ?

The equivalent mass of divalent metal is W. The molecular mass of its chloride is :

A metal nitride M_(3)N_(2) contains 28 % of nitrogen. The atomic mass of metal M is

The equivalent mass of dilvalent metal is W. The molecular mass of its chloride is:

The percentage of element M is 53% in its oxide of molecular formula M_(2)O_(3) . Its atomic mass is about

Compound of a metal A is M_2O_3 , the formula of its halide is

The equivalent mass of a metal is twice to that of oxygen. How many times the weight of it's oxide is greater than the weight of metal?

56 g of an element M combines with 16 g of oxygen to form its oxide of type MO. Find out (a) Equivalent mass of element (b) Equivalent mass of oxide (Assume law of conservation of mass to be valid).