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Ionic solid Na^(+)A^(-) crystallise in r...

Ionic solid `Na^(+)A^(-) `crystallise in rock salt type structure. 2.6gm of ionic solid salt NaA dissolved in water to make 2 litre solution.The pH of this solution is 8. If distance between cation and anion is 300pm calculate density of ionic solid `(ingm/cm^(3)) .(Given: pK_(w)=13 pK_(a)(HA)=5 N_(A)=6 `

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Ionic solid Na^(+) A^(-) crystallise in rock salt type structure . 2.592 gm of ionic solid salt NaA dissolved in water to make 2 litre solution . The pH of this solution is 8. If distance between cation and anion is 300 pm. Calculate density of ionic solid (P low =13,P low (HA)=13)

Ionic solid B^+A^(-) crystallizes in rock salt type of structure.1.296 gm ionic solid salt B^+A^(-) is dissolved in water to make one litre solution.The pH of the solution is measured to be 6.0.if the value of face diagonal in the unit cell of B^+A^(-) be 600sqrt2 pm.Calculate the density of ionic solid in gm/cc. (T=298 K, K_b "for" BOH "is" 10^(-6) ,(Avogadro Number = 6.0xx10^(23) ))

The crystal AB (rock salt structure) has molecular weight 6.023Y u , where Y is an arbitrary number in u . If the minimum distance between cation and anion is Y^(1/3) nm . Find the density in kg m^(-3) .

The crystal AB (rock salt structure) has molecular weight 6.023 y u, where y is an arbitrary number in u. If the minimum distance between cation and anion is y^(1//2) nm and the observed density is 20kg/ m^(3) , find the (i) density in kg/ m^(3) and (ii) type of defect.

A solid cube of edge length =25.32 mm of an ionic compound which has NaCl type lattice is added to 1kg of water.The boiling point of this solution is found to be 100.52^@C (assume 100% ionisation of ionic compound).If radius of anion of ionic solid is 200 pm then calculate radius of cation of solid in pm (picometer). ( K_b of water =0.52 K kg "mole"^(-1) ,Avogadro's number, N_A=6xx10^(23),(root3(75))=4.22 )

How many gm of solid KOH must be added to 100 mL of a buffer solution to make the pH of solution 6.0, if it is 0.1 M each w.r.t. acid HA and salt K A. [Given : pK_(a)(HA)=5]

Calculate approximate pH of the resultant solution formed by titration of 25 mL of 0.04 M Na_(2)CO_(3) with 50 mL of 0.025 M HCl. [Given : pK_(a1)=6.4 and pK_(a2)=10.3 for H_(2)CO_(3)]

When NaOH solution is gradually added to the solution of weak acid (HA), the pH of the solution is found to be 5.0 at the addition of 10 and 6.0 at further addition of 10 ml of same NaOH. (Total volume of NaOH =20ml). Calculate pK_(a) for HA. [log2 = 0.3]

NaCl is a AB type of solid . Its crystalline structure is known as rock salt structure in which r_"Na"^+ and r_"Cl"^- are 95 and 181 pm respectively , where Cl^- is present at the lattice point of face centered cubic unit cell Na^+ ions are located in void and those compounds which have same crystalline structure also have same coordination system in which Na^+ and Cl^- ions are surrounded by certain number of opposite ions respectively. Under high pressure coordination number changes to 8 :8 type from 6 :6 type. In rock salt type structure of AB solid , what would be the maximum radius of 'X' that can displace A^+ if radius of B^- is 100 pm ?

5.35 g of a salt Acl (of weak base AOH) is dissolved in 250 ml of solution. The pH of the resultant solution was found to be 4.827. Find the ionic radius of A^(+) and Cl^(-) if ACl forms CsCl type crystal having 2.2 g/cm3. Given K_(b(AOH))=1.8xx10^(-5), (r^(+))/(r^(-))=0.732 for this cell unit.