Solve:
`-10=10 t+1/2(-10)t^2`

Solve- 10-10 times 10+10

The displace ment of a body at any time t after starting is given by s=10t-(1)/(2)(0.2)t^2 . The velocity of the body is zero after:

Solve: (1/2)^(log^(10a^2))+2>3/(2^((log)_(10)(-a)))

Solve: 1/(x+1)+1/(x+2)=2/(x+10)

Solve : (2x+1)/(3x-2)=9/(10)

Solve |x-1|^((log_(10) x)^2-log_(10) x^2=|x-1|^3

Solve the equation. t/5=10

Solve the equation 10^((x+1)(3x+4))-2*10^((x+1)(x+2))=10^(1-x-x^(2)).

The phase difference between two SHM y_(1) = 10 sin (10 pi t + (pi)/(3)) and y_(2) = 12 sin (8 pi t + (pi)/(4)) to t = 0.5s is

Solve for x : sin(x+10^(@))=1/2