Ionisation constant of water at `25^(@)`C is equals to
A) 15.00
B) 14.00
C) 13.90
D) 12.55

Dissociation constant of water at 25^(@) C is

The ionic product of water at 25^@C is 10^(-14) its ionic product at 90^@C will be

sec^2(tan^(01)2)+cos e c^2(cot^(-1)3) is equal to 5 (b) 13 (c) 15 (d) 6

9+|-4| is equal to: (a)5 (b) -5 (c) 13 (d) -13

The line x=c cuts the triangle with corners (0,0),(1,1) and (9,1) into two region. two regions to be the same c must be equal to (A) 5/2 (B) 3 (C) 7/2 (D) 5 or 15

(-16)+14-(-13) is equal to: (a) -11 (b) 12 (c) 11 (d) -15

If 1^2+2^2+3^2+n^2=1015 then the value of n is equal to (A) 13 (B) 14 (C) 15 (D) none of these

In the figure, if A B=A C ,/_B A D=30^0 and A E=A D , then x is equal to a) 15^0 (b) 10^0 (c) 12. 5^0 (d) 7. 5^0

The mean deviation about median of variates 13, 14, 15,...., 99, 100 is 1936 (b) 21.5 (c) 23.5 (d) 22

The dissoctiation of water of 25^(@)C is 1.9 xx 10^(-7)% and the density of water is 1g//cm^(3) the ionisation constant of water is