A body weighs 180N on the surface of the earth.How much will it weigh at depth `R_(e)`/2 from surface of the earth. (`R_(e)`= Radius of earth ).

A body weight 500 N on the surface of the earth. How much would it weigh half way below the surface of the earth

A body weighs 200N on the surface of the earth. How much will it weigh half way down to the center of the earth ?

A body weighs 250N on the surface of the earth. How much will it weighs half way down to the centre of the earth?

A man weighs 'W' on the surface of the earth and his weight at a height 'R' from surface of the earth is ( R is Radius of the earth )

An object weighs 60 N at the surface of earth. How much will it weigh at the surface of the moon ? ["Given" g_(m)=(1)/(6)g_(e)]

A body weighs W newton at the surface of the earth. Its weight at a height equal to half the radius of the earth, will be

A body weighs W newton at the surface of the earth. Its weight at a height equal to half the radius of the earth, will be

If a man weighs 90 kg on the surface of the earth, the height above the surface of the earth of radius, R where the weight is 30 kg is

The acceleration due to gravity at a depth R//2 below the surface of the earth is

A particle is given a velocity (v_(e ))/(sqrt(3)) in a vertically upward direction from the surface of the earth, where v_(e ) is the escape velocity from the surface of the earth. Let the radius of the earth be R. The height of the particle above the surface of the earth at the instant it comes to rest is :