A galvanometer has a current range of 0 to 1mA and voltage range 50mV .The shunt required to convert this into an ammeter range 0.1A is

A galvanometer has a current range of 15mA and voltage range of 750mv. To convert this galvanometer into an ammeter of range 25A, the sunt resistance required is nearly

The resistance of galvanometer is g ohm and the range is 1 volt. The value of resistance used to convert it into a voltmeter of ragne 10 volt is:-

Current passing through galvanometer is 0.002A and resistance of galvanometer is R_(g)=50Omega find out shunt resistance to convert it into ammeter of range 0.5 A

A galvanometer coil has a resistance of 990Omega and it shows full scale deflection for a current of 10mA. Calculate the value of resistance required to convert it into an ammeter of range 1 A.

A galvanometer has resistance G and full scale deflection current i. To convert this galvanometer into an ammeter of range 10 I, a shunt S = (G)/(9) is connected in parallel with G. Now we want to measure potential difference with the help of this ammeter. What is the maximum value of potential difference which can be measured with the help of this?

The resistance of a galvanometer coil is R. What is the shunt resistance required to convert it into an ammeter of range 4 times

A galvanometer of resistance 100Omega gives full deffection for a current 10^(-5) the value of shunt required to convert it into ammeter of range 1 ampere is:-

A moving coil galvanometer allows a full scale current of 10^(-4) A. A series resistance of 2 Momega is required to convert the above galvonometer into a voltmeter of range 0-5 V. Therefore the value of shunt resistance required to convert the above galvanometer into an ammeter of range 0-10 mA is: a) 500Ω b) 100Ω c) 200Ω d) 10Ω

If a galvanometer has full scale deflection current I_(g) and resistance G. A shunt resistance R_(A) is used to convert it into an ammeter of range I_(o) and a resistance R_(V) is connected in series to convert it into a voltmeter of range V_(0) such that V_(0)=I_(0)G then R_(A)R_(V) and (R_(A))/(R_(V)) respectively are:

The range of voltmeter of resistance 300 Omega is 5 V. The resistance to be connected to convert it into an ammeter of range 5 A is