The time period of an oscillation body executing SHM is 0.2`pi` sec .and its amplitude is "20cm" .The maximum velocity of particle is:-

A particle executes SHM with time period T and amplitude A . The maximum possible average velocity in time T//4 is-

The amplitude of a particle executing SHM about O is 10 cm . Then

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

A particle executing SHM with time period T and amplitude A. The mean velocity of the particle averaged over quarter oscillation, is

The time period of a particle executing SHM is T . After a time T//6 after it passes its mean position, then at t = 0 its :

A particle is executing SHM with amplitude 4 cm and has a maximum velocity of 10 cm/sec What is its velocity at displacement 4 cm/sec ?

A particle is executing SHM with amplitude 4 cm and has a maximum velocity of 10 cm/sec What is its velocity at displacement 2 cm?

A particle is executing S.H.M. with amplitude A and has maximum velocity v_(0) . Its speed at displacement (3A)/(4) will be

The maximum velocity of a particle executing simple harmonic motion is v. If the amplitude is doubled and the time period of oscillation decreased to 1/3 of its original value the maximum velocity becomes

A particle of mass 10g is undergoing SHM of amplitude 10cm and period 0.1s. The maximum value of force on particle is about