A battery of e.m.f. E ,internal resistance r is applied in the circuit in a closed loop. The current I in the circuit goes from the positive terminal of the battery to the negative terminal inside it. The potential drop across the battery is

A 3 volt battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

Consider the circuit shown in the figure. Taking the potential to be zero at the negative terminal of the battery :

A battery of emf 2.0 V and internal resistance 0.10 Omega is being charged with a current of 5.0 A . Find the potential difference between the terminals of the battery?

A battery of emf 2.0 volts and internal resistance 0.10(Omega) is being charged with a current of 5.0A. What is the potential difference between the terminals of the battery?

A battery of emf 15 V and internal resistance of 4Omega is connected to a resistor. If the current in the circuit is 2A and the circuit is closed. Resistance of the resistor and terminal voltage of the battery will be

A car battery with a 12V e.m.f. and an internal resistance of 0.04 Omega is being charged with a current of 50A. The potential difference V across the terminals of the battery are:

n' cells , each of emf 'e' and internal resistance 'r' are connected in a closed circuit so that the positive terminal of a cell is joined to the negative terminal of the next, as shown in figure. Any two points of the circuit are connected by an external resistance R. Find the current in R.

An electron moves from the positive to the negative terminal of a battery (9 V). How much potential energy did it gain or lose ?

A battery of emf 10 V and internal resistance 3 Omega is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistors ? What is the terminal voltage of the battery when the circuit is closed ?

A battery of emf 2 V and initial resistance 1 Omega is connected across terminals A and B of the circuit shown in figure .