A periodic function is given as "sin `omega` t+cos `omega` t" The amplitude of this function is given by
A) 2`sqrt(2)` B) 2 C) 2.13 D) 1.414

The SHM of a particle is given by the equation x=2 sin omega t + 4 cos omega t . Its amplitude of oscillation is

Current in an ac circuit is given by I= 3 sin omega t + 4 cos omega t, then

Find time period of the function, y=sin omega t + sin 2omega t + sin 3omega t

If i_(1)=3 sin omega t and (i_2) = 4 cos omega t, then (i_3) is

The displacement of a particle performing simple harmonic motion is given by, x=8 "sin" "omega t + 6 cos omega t, where distance is in cm and time is in second. What is the amplitude of motion?

The displacement of two interfering light waves are y_(1)=4 sin omega t" and "y_(2)= 3 cos (omega t) . The amplitude of the resultant waves is (y_(1)" and "y_(2) are in CGS system)

Find the integral of the given function w.r.t.x.: sqrt((9x)-4x^(2))

An alternating voltage is given by: e = e_(1) sin omega t + e_(2) cos omega t . Then the root mean square value of voltage is given by:

An alternating voltage is given by: e = e_(1) sin omega t + e_(2) cos omega t . Then the root mean square value of voltage is given by:

Find the integral of the given function w.r.t. x. 1/\sqrt {2x-x^2}