`x^2+y^2/b^2=1` Find `dy/dx`

x^(2)/a^2+y^2/b^2=1 find (dy)/(dx)

If (x^2)/(a^2)+(y^2)/(b^2)=1 , find (dy)/(dx)

If x^2+y^2=x-y Find dy/dx

y=(x^2+1/x^2)^3 find dy/dx

If (x^2+y^2)^2=x y , find (dy)/(dx)

If (x^2+y^2)^2=x y , find (dy)/(dx)

y=x^(3/2) find dy/dx

If x y=c^2 , find (dy)/(dx)

If a x^2+2\ h x y+b y^2+2\ gx+2\ fy+c=0 , find (dy)/(dx) and (dx)/(dy) . Also, show that (dy)/(dx)dot(dx)/(dy)=1 .

y=x^(2)+(1)/(x^(2)) . Find (dy)/(dx)