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The set of Quantum numbers that is not p...

The set of Quantum numbers that is not possible for a d-electron (A) n=3;l=2;m=0;s=+1/2 (B) n=2;l=2;m=-2;s=+1/2 (C) n=4;l=2;m=+2;s=+1/2 (D) n=4;l=2;m=-1;s=-1/2

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The set of quantum numbers, n = 3, l = 2, m_(l) = 0

Which of the following sets of quantum numbers represents the highest energy of an electron? (A) n = 5, l = 0, m = 0, s = +1/2 (B) n = 6, l = 2, m = 1, s = +1/2 (C) n = 5, l = 1, m = 1, s = -1/2 (D) n = 4, l = 1, m = 0 s = -1/2

The set of quantum numbers, n = 2, l = 2, m_(l) = 0 :

The following quantum numbers are possible for how many orbitals (s) n = 3, l = 2, m = + 2 ?

Explain giving reasons, which of the following sets of quantum numbers are not possible? (a) n=0, l=0, m_(l)=0, m_(s)=+1/2 (b) n=1, l=0, m_(l)=0, m_(s)=-1/2 (c) n=1, l=1, m_(l)=0, m_(s)=+1/2 (d) n=2, l=1, m_(l)=0, m_(s)=-1/2 (e) n=3, l=3, m_(l)=-3, m_(s)=+1/2 (f) n=3, l=1, m_(l)=0, m_(s)=+1/2

From the following sets of quantum numbers , state which are possible ? (i) n=0,l=0,m_(l)=1,m_(s)= +1//2 (ii) n=2,l=1,m_(l)=0,m_(s) = -1//2 (iii) n=2, l=0,m_(1)=3,m_(s) = +1//2 (iv) n=3,l=1,m_(l)=0,m_(s) = +1//2

Arrange the following set of quantum number highest energy of an electron. {:((p) n=4,i=1,m=+1,s=+(1)/(2)),((1) n=4,i=2,m=-1,s=-(1)/(2)),((r) n=3,i=2,m=0,s=+(1)/(2)),((s) n=3,i=1,m=+1,s=-(1)/(2)):}

Among the following sets of quantum number, state which are possible. Explain why the other are not permitted? (a) n=1, l=0, m=-1, s=+1/2 (b) n=, l=0, m=0, s=-1/2 (c ) n=2, l=3, m=0, s=-1/2 (c ) n=2, l=3, m=0, s=+1/2 (d) n=3, l=1, m=1, s=-1/2 (e ) n=0, l=0, m=0, s=+1/2 (f ) n=2, l=0, m=0, s=-1/2

Arrange the electrons represented by the following sets of quantum numbers in decreasing order of energy. (i) n=4, l=0, m_(l)=0, s=+1//2 , (ii) n=3, l=1, m_(l)=1, s=-1//2 (iii) n=3, l=2, m_(l)=0, s=+1//2 , (iv) n=3, l=0, m_(l)=0, s=-1//2

Which of the following sets of quantum numbers do not belong to 2p subshell? (i) n=2, l=1, m=+1, s=+1/2 (ii) n=2, l=0, m=0, s=-1/2 (iii) n=1, l=1, m=0, s=+1/2