The CFSE for octahedral low spin complex for `d ^(4)` electronic configuration is 'x' `cm^(-1)` ,the value of `|(x)/(700)|` [Dq=`2100cm^(-1)` Pairing energy =`28,000cm^(-1)`

Electronic configuration od d^8 system in low spin octahedral complex

In the general electronic configuration (n-2)^f(1-14) (n-1)^d(0-1) ns^2 ,if the value of n=7,the configuration will be of

CFSE for d^(6) octahedral complex having Delta =250 and P =125kJmo1^(-1) is .

If 1 g cm s^(-1) = x Ns , then what is the value of x ?

In the followin electronic configuration, ns^(2)(n-1)d^(0-1)(n-2)f^(1-14) If value of (n-1)=5 the configuration will be of :-

The CFSE for octahedral [CoCl_(6)]^(4-) is 18,000 cm^(-1) . The CFSE for tetrahedral [CoCl_(4)]^(2-) will be

The CFSE for octahedral [CoCl_(6)]^(4-) is 18,000 cm^(-1) . The CFSE for tetrahedral [CoCl_(4)]^(2-) will be

Determine the crystal field stabilisation energy of a d^(6) complex having Delta_(0) = 25000cm^(-1) and P =1500cm^(-1) .

A semiconductor is known to have an electron concentration of 5x10^(12) cm^(-3) and a hole concentration 8x10^(13) cm^(-3) . (i)Is the semiconductor n-type of p-type ? (ii)What is the resistivity of the sample. If the electron mobility is 23,000 cm^(2)v^(-1)s^(-1) ' and hole mobility is 100cm^(2)v^(-1)s^(-1) ' Take charge on electron, e=.16x10^(-19)c.

For the complex [Cr(H_(2)O)_(6)]^(2+) calculate the total pairing energey in high spin and low spin state Given the mean pairing energey =23500cm^(-1) .