The rate constant for a certain gaseous reaction is \(3\times10^{-2}mol^{-1}dm^{3}s^{-1}\) at 293 K. What will be the value if expressed in `atm^-1``s^-1`

The activation energy and enthalpy of chemisorption of oxygen on a metal surface is 37.3kJ mol^(-1) and -72.1kJ mol^(-1) At a certain pressure, the rate constant for chemisorption is 1.2xx10^(-3) at 318 K . What will be the value of the rate constant at 308K ?

The rate constant of a reaction is 6 × 10^-3 s^-1 at 50° and 9 × 10^-3 s^-1 at 100° C. Calculate the energy of activation of the reaction.

For a reaction the activation energy E_a=0 and the rate constant= 3.2 times 10^6 sec^-1 at 300K. What is the value of rate constant at 310K?

Rate constant of a reaction (k) is 3 xx 10^(-3) "litre"^(2) "mol"^(-2)sec^(-1) . What is the order of reaction ?

Rate constant of a reaction (k) is 3 xx 10^(-2) "litre"^(-1) molsec^(-1) . What is the order of reaction ?

Rate constant of a reaction (k) is 2 xx 10^(-3) "litre"^(2) "mol"^(-2)sec^(-1) . What is the order of reaction ?">

The rate constant for the reaction in gaseous phase O+O_(3) rarr 2O_(2) is 8.0xx10^(-15)" cm"^(3)" molecule"^(-1) s^(-1) at 298 K. Corresponding value in dm^(3)" mol"^(-1) s^(-1) is :

If the rate constant k of a reaction is 1.6 times 10^–3(mol//l)(min^–1) . The order of the reaction is:

Rate constant of a reaction (k) is 4 xx 10^(-2) "litre"^(-1) molsec^(-1) . What is the order of reaction ?

Rate constant of a reaction (k) is 2 xx 10^(-2) "litre"^(2) "mol"^(-2)sec^(-1) . What is the order of reaction ?