A solid cylinder starts rolling from a height h on an inclined plane. At some instant t, the ratio of its rotational K.E and the total K.E would be

A solid cylinder is rolling without slipping down an inclined plane. Then its angular momentum is :

A solid cylinder rolls down an inclined plane from a height h. At any moment the ratio of rotational kinetic energy to the total kinetic energy would be

A solid cylinder starts rolling down on an inclined plane from its top and V is velocity of its centre of mass on reaching the bottom of inclined plane. If a block starts sliding down on an identical inclined plane but smooth, from its top, then the velocity of block on reaching the bottom of inlined plane is

A disc rolls on a table. The ratio of its K.E. of rotation to the total K.E. is -

A solid cylinder (i) rolls down (ii) slides down an inclined plane. The ratio of the accelerations in these conditions is

Ratio of rotational K.E. to rolling KE. of a solid sphere is