A body of mass 2 kg is driven by a force F. The position of the body changes with time as `(3 t^2 hati + 2t hatj)`, where the distance is in metre and time in seconds. Find the magnitude of the force F.

The position of a particle is expressed as vecr = ( 4t^(2)hati + 2thatj) m. where t is time in second. Find the acceleration of the particle.

The position x of a particle moving along x - axis at time (t) is given by the equation t=sqrtx+2 , where x is in metres and t in seconds. Find the work done by the force in first four seconds

A force acts for 0.1 s on a body of mass 2.0 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2 "m s"^(-1) . Find the magnitude of the force.

Due to the application of a force on a body of mass 100 kg that is initially at rest, the body moves with an acceleration of 20ms^(-2) in the direction of the force. Find the magnitude of the force.

A force acts for 0.1 s on a body of mass 2 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2 m/s. Find the magnitude of force.

If x= at + bt^(2) , where x is the distance travelled by the body in kilometer while t is the time in seconds , then find the units of b .

If x= at + bt^(2) , where x is the distance rtravelled by the body in kilometer while t is the time in seconds , then find the units of b .

The position vector of a particle changes with time according to the direction vec(r)(t)=15 t^(2)hati+(4-20 t^(2))hatj . What is the magnitude of the acceleration at t=1?

A force acts on a 3.0 gm particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where xx is in metres and t is in seconds. The work done during the first 4 seconds is

A force acts for 0.1 s on a body of mass 1.2 kg initially at rest. The force then ceases to act and the body moves thorugh 2 m in the next 1.0 s . Find the magnitude of force.