A man throws a ball vertically upward and it rises through 20m and returns to his hands. What was the initial velocity (u) of the ball and for how much time (T) it remained in the air? (Take g=10m`s^(-1)` )

A ball is thrown vertically upwards. It returns 6 s later. Calculate the initial velocity of the ball. (Take g = 10 "m s"^(-2) )

A ball is thrown vertically upwards. It goes to a height 19.6 m and then comes back to the ground, Find the initial velocity of the ball . Take g = 9.8 m s^(-2)

When a ball is thrown vertically upwards it goes through a distance of 19.6 m. Find the initial velocity of the ball and the time taken by it to rise to the high point (Acceleration due to gravity g=9.8 m/s^(2))

A ball is thrown vertically upwards. It goes to a height 19.6 m and then comes back to the ground, Find the final velocity of the ball when it strikes the ground. Take g = 9.8 m s^(-2)

A ball is thrown vertically upward with a speed of 20 m/s. Draw a graph showing the velocity of the ball as a function of time as it goes up and then comes back.

A ball of mass 50 g is dropped from a height of 20 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 200 N, so that it attains a vertical height of 45 m. The time for which the ball remains in contact with the bat is [Take g=10m//s^(2)]

Two balls of equal masses are thrown upwards, along the same vertical direction at an interval of 2 seconds, with the same initial velocity of 40m//s . Then these collide at a height of (Take g=10m//s^(2) ).

A ball is thrown vertically upward attains a maximum height of 45 m. The time after which velocity of the ball become equal to half the velocity of projection ? (use g = 10 m//s^(2) )

A man throws ball with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two ball are in the sky at any time (Given g=10(m)/(2^2) )

An object is thrwon vertically upwards with a velocity of 60 m/s. After what time it strike the ground ? Use g=10m//s^(2) .