If `900g` of water at `90^(@)C` is to be cooled to `40^(@)C` by adding ice at `0^(@)C` ,the mass (in grams) of the ice required is (Latent heat of ice is 80kcal/kg ,specific heat of water is 1kcal/`kg^(@)C`.

If 10 g of ice at 0^(@)C is mixed with 10 g of water at 40^(@)C . The final mass of water in mixture is (Latent heat of fusion of ice = 80 cel/g, specific heat of water =1 cal/g""^(@)C )

The temperature of 300 g of water at 40^@ C is lowered to 0^@ C by adding ice to it. Find the mass of ice added if specific heat capacity of water is 4.2 J g^(-1) K^(-1) and specific latent heat of ice is 336 J g^(-1)

10 gram of water at 45^(@)C is added to 5 gram of ice at -30^(@)C . Find the final temperature of the mixture. Specific heat of ice is 0.55 cal g^(-1)""^(@)C^(-1) and that of water is 1.0 cal g^(-1)""^(@)C^(-1) latent heat of fusion of ice is 80 cal g^(-1) ? (ii) To rise the temperature of 100 gram of water from 24^(@) to 90^(@)C by steam at 100^(@)C . Calculate the amount of steam required. Specific heat of water is 1.0 cal g^(-1)""^(@)C^(-1) . Latent heat of steam is 540 Cal kg^(-1) .

The amount of heat required to raise the temperature of 75 kg of ice at 0^oC to water at 10^oC is (latent heat of fusion of ice is 80 cal/g, specific heat of water is 1 cal/ g^oC )

An iron ball of mass 0.2 kg is heated to 10^(@)C and put into a block of ice at 0^(@)C . 25 g of ice melts. If the latent heat of fusion of ice is 80 cal g^(-1) , then the specific heat of iron in cal g^(-1^(@))C is

When 1 kg of ice at 0^(@)C melts to water at 0^(@)C , the resulting change in its entropy, taking latent heat of ice to be 80 cal//g is

A cube of ice of mass 30 g at 0^@ C is added into 200 g of water at 30^@ C. Calculate the final temperature of water when whole of the ice cube has melted. Given: specific latent heat of ice = 80 cal g^(-1) , specific heat capacity of water = 1 cal g^(-1)^@C^(-1)

80 g of water at 30^@C are poured on a large block of ice at 0^@C . The mass of ice that melts is

80 g of water at 30^@C are poured on a large block of ice at 0^@C . The mass of ice that melts is

1 kg of ice at 0^(@)C is mixed with 1.5 kg of water at 45^(@)C [latent heat of fusion = 80 cal//gl. Then