Home
Class 12
PHYSICS
If the speed v of a charged particle mov...

If the speed v of a charged particle moving in a magnetic filed `vec(B)` ( `vec(v)` is perpendicular to `vec(B)`) is halved , then the radius of its path will:

A

not change

B

become two times

C

become one- fourth

D

become half

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER 2022 TERM 1 SET 2

    XII BOARDS PREVIOUS YEAR|Exercise SECTION B|24 Videos
  • QUESTION PAPER 2022 TERM 1 SET 2

    XII BOARDS PREVIOUS YEAR|Exercise SECTION C|6 Videos
  • QUESTION PAPER 2022 TERM 1 SET 1

    XII BOARDS PREVIOUS YEAR|Exercise SECTION-C|6 Videos
  • QUESTION PAPER 2023

    XII BOARDS PREVIOUS YEAR|Exercise Question|43 Videos

Similar Questions

Explore conceptually related problems

If vec(A) is perpendicular to vec(B) , then

If vec(v)_(1)+vec(v)_(2) is perpendicular to vec(v)_(1)-vec(v)_(2) , then

A particle of mass m, charge e and velocity v moving in a magnetic field B perpendicular to the motion of particle. The radius of its path is:

If vec a+vec b is perpendicular to vec b and vec a+vec 2b is perpendicular to vec a then

Given that vec(A)+vec(B)=vec(R) and vec(A)+2vec(B) is perpendicular to vec(A) . Then :-

If a charged particle goes unaccelerated in a region containing electric and magnetic fields, (i) vec(E) must be perpendicular to vec(B) (ii) vec(v) must be perpendicular to vec(E) (iii) vec(v) must be perpendicular to vec(B) (iv) E must be equal to v B

When a charged particle moving with velocity vec(V) is subjected to a magnetic field of induction vec(B) the force on it is non-zero. This implies that:

Let vec a,vec b and vec c are vectors of magnitude 3,4,5 respectively.If vec a is perpendicular to vec b+vec c,vec b is perpendicular to vec c+vec a and vec c is perpendicular to vec a+vec b then find the magnitude of vec a+vec b+vec c

As a charged particle 'q' moving with a velocity vec(v) enters a uniform magnetic field vec(B) , it experience a force vec(F) = q(vec(v) xx vec(B)). For theta = 0^(@) or 180^(@), theta being the angle between vec(v) and vec(B) , force experienced is zero and the particle passes undeflected. For theta = 90^(@) , the particle moves along a circular arc and the magnetic force (qvB) provides the necessary centripetal force (mv^(2)//r) . For other values of theta (theta !=0^(@), 180^(@), 90^(@)) , the charged particle moves along a helical path which is the resultant motion of simultaneous circular and translational motions. Suppose a particle that carries a charge of magnitude q and has a mass 4 xx 10^(-15) kg is moving in a region containing a uniform magnetic field vec(B) = -0.4 hat(k) T . At some instant, velocity of the particle is vec(v) = (8 hat(i) - 6 hat(j) 4 hat(k)) xx 10^(6) m s^(-1) and force acting on it has a magnitude 1.6 N Motion of charged particle will be along a helical path with