An electrolyte AB dissociates to an extent of 80% in water. Then the value of 'i'. i.e., Vant Hoff's factor is?

Vant Hoff factor (i)-

If BaCl_(2) ionizes to an extent of 80% in aqueous solution the value of Vant't Hoff factor is

If van't Hoff factor i=1,then

In case of electrolyte which dissociates in the solution the van Hoff factor I

Define (i) Mole fraction (ii) Van't Hoff factor.

The experimental molecular weight of an electrolyte will always be less than its calculated value because the value of Van't Hoff factor. 'i, is:

An electrolyte AB is 50% dimerise and rest is ionise in a solvent , then vant't hoff factor for this acid is

An electrolyte A_(2)B_(3) ionizes in water upto 75%. The van't Hoff factor for it is .