Let R be the region bounded by `yx^4-1+yle0`, `yge0` and `0lexle1`. If S be the area of region R, then

The area of the region bounded by y^(2)=2x+1 and x-y-1=0 is

Let R be the region satisfying 'yx-1,x 0, then area of R is

The area of the region bounded by y=1+|x+1|,x=-3,x=3,y=0 is

The area of the region bounded by curves y=1-x^(2), x+y+1=0 and x-y-1=0 is

The area of the region bounded by y = x^(2) and y = 4x , for x between 0 and 1 is equal to

The line x = (pi)/(4) divides the area of the region bounded by y = sin x, y = cos x and X-axis (0lexle(pi)/(2)) into two regions of areas A_(1) and A_(2) . Then, A_(1) : A_(2) equals

The solution set of xge5, yge0 and xle5,yle0 is