If the area of the triangle having vertices (2,-5),(5,4) and (k,4) is 35 sq. units, then find the value of k.

If the area of a triangle with vertices (-3,0),(3,0) and (0,0) is 9 sq. units. Then the value of k will be

Find the area of the triangle, whose vertices are (2,1), (4,5) and (6,3).

find the area of triangle whose vertices are (3,8),(-4,2)and (5,1)

Find the area of that triangle whose vertices are (2,3),(-3,4)and(7,5).

Find the area of the triangle whose vertices are: (-2,4),(2,-6),(5,4)

Find the area of the triangle whose vertices are: (3,1),(4,3),(-5,4)

Find the area of the triangle whose vertices are: (-3,2),(5,4),(7,-6)

Find the area of the triangle whose vertices are: (2,8),(-4,2),(5,1)

Find the values of k so that the area of the triangle with vertices (1, -1), (-4, 2k) and (-k, -5) is 24 sq. units.

If the vertices of a triangle are (1,2),(4,k)and(7,8) and its area is 15 sq. units, then the value(s) of k is