The least possible integer value of a, so that the line `(3-a)x+ay+a^2-1=0` is normal to the curve `xy=1` is

The value of the parameter a so that the line (3-a)x+ay+ a^2-1=0 is normal to the curve xy=1 may lie in the interval

The value of parameter t so that the line (4-t)x+ty+(a^(3)-1)=0 is normal to the curve xy = 1 may lie in the interval

Find the condition that the line A x+B y=1 may be normal to the curve a^(n-1)y=x^ndot

Find the condition that the line A x+B y=1 may be normal to the curve a^(n-1)y=x^ndot

Find the condition that the line A x+B y=1 may be normal to the curve a^(n-1)y=x^ndot

If Ax+By=1 is a normal to the curve ay=x^(2) , then :

What is the greatest integer value of x such that 1-2x is at least 6?

The least integer value of x , which satisfies |x|+|(x)/(x-1)|=(x^(2))/(|x-1|) is

The least positive integral value of 'k' for which there exists at least one line that the tangent to the graph of the curve y=x^(3)-kx at one point and normal to the graph at another point is

The set of real values of 'a' for which at least one tangent to y^(2)=4ax becomes normal to the circle x^(2)+y^(2)-2ax-4ay+3a^(2)-0, is