A potential difference of 3000V is maintained between two large parallel plates 6cm apart . The force on a proton midway between the plates is `x× 10^-15` N. what is the value of x.

A potential difference of 600 V is applied across the plates of a parallel plate condenser. The separation between the plates is 3 mm. An electron projected vertically, parallel to the plates, with a velocity of 2xx10^(6)m//s moves undeflected between the plates. Find the magnitude of the magnetic field (in T) in the region between the condenser plates. (Neglect the edge effects) square . (Charge of the electron =1.6xx10^(-19)C )

A potential difference of 600 volts is applied across the plates of a parallel plate consenser . The separation between the plates is 3mm . An electron projected vertically, parallel to the plates , with a velocity of 2 xx 10^(6) m//sec moves underflected between the plates. Find the magnitude and direction of the magnetic field in the region between the condenser plates. ( Neglect the edge effects). ( Charge of the electron = -1.6xx10^(-19) coulomb)

The parallel plate capacitor has potential difference of 100 V and separation between the plate is 1 mm. An electron is projected along x axis in between the plates. If the electron comes out of the plates along the x axis undevated then the magnitude and direction of magnetic field that must be applied between the plates : (particle is projected with a velocity of 10^5 m//s along x axis)

What is the area of the plates of a 2 farad parallel plate air capacitor, given that the separation between the plates is 0.5 cm?

What is the area of the plates of a 2 farad parallel plate air capacitor, given that the separation between the plates is 0.5 cm?

A parallel plate capacitor with area 200 cm^(2) and separation between the plates 1.5 cm is connected across a battery of emf V if the force of attraction between the plates is 25xx10^(-6) N the value of V is approximately : epsilion_(0)=8.85xx10^(12)(C^(2))/(N.m^(2))

Figure shows a parallel plate capacitor with plate area A and plate separation d . A potential difference is being applied between the plates. The battery is then disconnected and a dielectric slab of dieletric constant K is placed in between the plates of the capacitor as shown. The electric field in the gaps between the plates and the electric slab will be

When a dielectric slab of thickness 6 cm is introduced between the plates of parallel plate condenser, it is found that the distance between the plates has to be increased by 4 cm to restore to capacity original value. The dielectric constant of the slab is

A parallel plate capacitor of plate area A and plates separation distance d is charged by applying a potential V_(0) between the plates. The dielectric constant of the medium between the plates is K. What is the uniform electric field E between the plates of the capacitor ?