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In each question, two equations numbered...

In each question, two equations numbered I and II have been given. You have to solve both the equations and mark the appropriate option.
I.`2x^2-13x+18=0`
II. `y^2-7y+12=0`

A

`x lt y`

B

`x ge y`

C

`x le y`

D

no relatioship can be established

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given equations step by step, we will start with the first equation and then move on to the second equation. ### Step 1: Solve the first equation \(2x^2 - 13x + 18 = 0\) 1. **Identify the coefficients**: Here, \(a = 2\), \(b = -13\), and \(c = 18\). 2. **Use the quadratic formula**: The quadratic formula is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] 3. **Calculate the discriminant**: \[ b^2 - 4ac = (-13)^2 - 4 \cdot 2 \cdot 18 = 169 - 144 = 25 \] 4. **Calculate the roots**: \[ x = \frac{13 \pm \sqrt{25}}{2 \cdot 2} = \frac{13 \pm 5}{4} \] - First root: \[ x_1 = \frac{13 + 5}{4} = \frac{18}{4} = 4.5 \] - Second root: \[ x_2 = \frac{13 - 5}{4} = \frac{8}{4} = 2 \] ### Step 2: Solve the second equation \(y^2 - 7y + 12 = 0\) 1. **Identify the coefficients**: Here, \(a = 1\), \(b = -7\), and \(c = 12\). 2. **Use the quadratic formula**: \[ y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] 3. **Calculate the discriminant**: \[ b^2 - 4ac = (-7)^2 - 4 \cdot 1 \cdot 12 = 49 - 48 = 1 \] 4. **Calculate the roots**: \[ y = \frac{7 \pm \sqrt{1}}{2 \cdot 1} = \frac{7 \pm 1}{2} \] - First root: \[ y_1 = \frac{7 + 1}{2} = \frac{8}{2} = 4 \] - Second root: \[ y_2 = \frac{7 - 1}{2} = \frac{6}{2} = 3 \] ### Summary of Solutions: - For the first equation, the solutions are \(x = 2\) and \(x = 4.5\). - For the second equation, the solutions are \(y = 3\) and \(y = 4\). ### Step 3: Determine the relationship between \(x\) and \(y\) - The values of \(x\) are \(2\) and \(4.5\). - The values of \(y\) are \(3\) and \(4\). ### Conclusion: - Comparing the values: - \(x = 2\) is less than \(y = 3\). - \(x = 4.5\) is greater than \(y = 4\). Since we have one value of \(x\) that is less than \(y\) and another value of \(x\) that is greater than \(y\), we cannot establish a consistent relationship between \(x\) and \(y\). Thus, the answer is that **no relationship can be established**.
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