Home
Class 14
MATHS
MLKJ is a trapezium. ABCD and PQRS are t...

MLKJ is a trapezium. ABCD and PQRS are two rhombuses. The diagonals of ABCD are 6cm and 8 cm. One of the angles of PQRS is 120 degrees and the diagonal bisecting that angle measures 15 cm. Side of ABCD = ML. Side of PQRS=JK. Find ON (median of the trapezoid).

A

10cm

B

12 cm

C

8 cm

D

15 cm

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

ABCD is a trapezoid. PQRS and MLKJ are two rhombus. Diagonal of PQRS are 6 cm and 8 cm. One of the angle of MLKJ is 120 degree and the diagonal bisecting that angle measures 15 cm. Side of PQRS = AB, side of MLKJ = CD. Find MN (median of trapezoid)

The diagonals of a rhombus are 8 cm and 15 cm. Find its side.

Diagonal of rhombus are 6 cm and 8 cm respectively, then find sides of rhombus.

Find the length of diagonal of a cube whose side is of measure 15cm.

Construct a rhombus PQRS with diagonal PR=3.4 cm and QS=3.6 cm.

The sides AD, BC of a trapezium. ABCD are parallel and the diagonals AC and BD meet at O. If the area of triangle AOB is 3 cm and the area of triangle BDC is 8 cm2, then what is the area of triangle AOD?