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Ram invests a certain sum in Scheme A of...

Ram invests a certain sum in Scheme A offering simple interest @`5%` pa for 4 years. He further invests the amount obtained from Scheme A into Scheme B offering compound interest @`10%` pa (compounded annually) . for 2 years. If the interest obtained from Scheme B was ₹378, then what was the sum invested in Scheme A? (in₹)

A

1200

B

1000

C

1600

D

1500

Text Solution

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The correct Answer is:
To solve the problem step by step, we need to break it down into manageable parts. ### Step 1: Define the initial investment Let the sum invested in Scheme A be \( x \) (in ₹). ### Step 2: Calculate the amount obtained from Scheme A Scheme A offers simple interest at a rate of 5% per annum for 4 years. The formula for calculating simple interest is: \[ \text{Simple Interest} = \frac{P \times R \times T}{100} \] Where: - \( P \) = Principal amount (initial investment) - \( R \) = Rate of interest per annum - \( T \) = Time in years For Scheme A: - \( P = x \) - \( R = 5\% \) - \( T = 4 \) Calculating the simple interest: \[ \text{Simple Interest} = \frac{x \times 5 \times 4}{100} = \frac{20x}{100} = \frac{x}{5} \] Now, the total amount obtained from Scheme A after 4 years is: \[ \text{Total Amount from Scheme A} = P + \text{Simple Interest} = x + \frac{x}{5} = \frac{5x}{5} + \frac{x}{5} = \frac{6x}{5} \] ### Step 3: Invest the amount in Scheme B The amount obtained from Scheme A, \( \frac{6x}{5} \), is then invested in Scheme B, which offers compound interest at a rate of 10% per annum for 2 years. ### Step 4: Calculate the compound interest from Scheme B The formula for compound interest is: \[ A = P \left(1 + \frac{R}{100}\right)^T \] Where: - \( A \) = Amount after time \( T \) - \( P \) = Principal amount - \( R \) = Rate of interest per annum - \( T \) = Time in years For Scheme B: - \( P = \frac{6x}{5} \) - \( R = 10\% \) - \( T = 2 \) Calculating the amount after 2 years: \[ A = \frac{6x}{5} \left(1 + \frac{10}{100}\right)^2 = \frac{6x}{5} \left(1 + 0.1\right)^2 = \frac{6x}{5} \left(1.1\right)^2 = \frac{6x}{5} \times 1.21 = \frac{6.726x}{5} \] ### Step 5: Calculate the compound interest earned The compound interest (CI) earned from Scheme B is given as ₹378. The CI can also be calculated as: \[ \text{CI} = A - P \] Where \( A \) is the amount after 2 years and \( P \) is the principal amount. Therefore: \[ \text{CI} = \frac{6.726x}{5} - \frac{6x}{5} = \frac{6.726x - 6x}{5} = \frac{0.726x}{5} \] Setting this equal to ₹378: \[ \frac{0.726x}{5} = 378 \] ### Step 6: Solve for \( x \) Multiplying both sides by 5: \[ 0.726x = 1890 \] Now, divide both sides by 0.726: \[ x = \frac{1890}{0.726} \approx 2600 \] ### Conclusion The sum invested in Scheme A is approximately ₹2600.
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