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For a meal in a restaurant, a customer g...

For a meal in a restaurant, a customer got a `10%` happy hour discount but paid `2.5%` CGST and `2.5%` SGST on the discounted rate. Had he got 200 as a discount and then paid the said taxes, he would have paid 42 more. What was the price of the meal before the discount?

A

RS... 3200

B

RS... 2400

C

RS... 2000

D

RS... 3600

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the original price of the meal before the discount. Let's break it down step by step. ### Step 1: Define the Variables Let the original price of the meal be \( X \) rupees. ### Step 2: Calculate the Price After the 10% Discount The customer receives a 10% discount on the meal. Therefore, the price after the discount is: \[ \text{Discounted Price} = X - 0.1X = 0.9X \] ### Step 3: Calculate the GST on the Discounted Price The customer pays 2.5% CGST and 2.5% SGST on the discounted price. Thus, the total GST is 5% of the discounted price: \[ \text{Total GST} = 0.05 \times 0.9X = 0.045X \] ### Step 4: Calculate the Total Amount Paid by the Customer The total amount paid by the customer after applying the discount and adding the GST is: \[ \text{Total Amount Paid} = 0.9X + 0.045X = 0.945X \] ### Step 5: Calculate the Price with a 200 Rupee Discount If the customer had received a flat discount of 200 rupees instead of 10%, the new price would be: \[ \text{New Price} = X - 200 \] ### Step 6: Calculate the GST on the New Price The GST on this new price would also be 5%: \[ \text{Total GST on New Price} = 0.05 \times (X - 200) = 0.05X - 10 \] ### Step 7: Calculate the Total Amount Paid with a 200 Rupee Discount The total amount paid with a 200 rupee discount would be: \[ \text{Total Amount with 200 Discount} = (X - 200) + (0.05X - 10) = 1.05X - 210 \] ### Step 8: Set Up the Equation According to the problem, the customer would have paid 42 rupees more with the 200 rupee discount: \[ 1.05X - 210 = 0.945X + 42 \] ### Step 9: Solve the Equation Rearranging the equation gives: \[ 1.05X - 0.945X = 210 + 42 \] \[ 0.105X = 252 \] \[ X = \frac{252}{0.105} = 2400 \] ### Conclusion The original price of the meal before the discount is \( 2400 \) rupees.
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