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In the following questions, two equation...

In the following questions, two equations numberded I and II are given. You have to solve both the equations and give answer If:
I. `x^2 - 13x+40=0` II. `y^2-16y+63=0`

A

`x lt y`

B

`x ge y`

C

`x gt y`

D

x= y or the relationship cannot be established

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given equations step by step, we will first tackle each equation separately. ### Step 1: Solve Equation I The first equation is: \[ x^2 - 13x + 40 = 0 \] To solve this quadratic equation, we will factor it. We need two numbers that multiply to \( 40 \) (the constant term) and add up to \( -13 \) (the coefficient of \( x \)). The factors of \( 40 \) that satisfy these conditions are \( -8 \) and \( -5 \): \[ (x - 8)(x - 5) = 0 \] Now, we set each factor to zero: 1. \( x - 8 = 0 \) → \( x = 8 \) 2. \( x - 5 = 0 \) → \( x = 5 \) So, the solutions for \( x \) are: \[ x = 5 \quad \text{and} \quad x = 8 \] ### Step 2: Solve Equation II The second equation is: \[ y^2 - 16y + 63 = 0 \] Similarly, we will factor this equation. We need two numbers that multiply to \( 63 \) and add up to \( -16 \). The factors of \( 63 \) that satisfy these conditions are \( -9 \) and \( -7 \): \[ (y - 9)(y - 7) = 0 \] Now, we set each factor to zero: 1. \( y - 9 = 0 \) → \( y = 9 \) 2. \( y - 7 = 0 \) → \( y = 7 \) So, the solutions for \( y \) are: \[ y = 9 \quad \text{and} \quad y = 7 \] ### Step 3: Compare Values of x and y Now we have the values: - For \( x \): \( 5 \) and \( 8 \) - For \( y \): \( 9 \) and \( 7 \) We will compare the values of \( x \) and \( y \): 1. If \( x = 5 \), then \( y = 7 \) → \( x < y \) 2. If \( x = 5 \), then \( y = 9 \) → \( x < y \) 3. If \( x = 8 \), then \( y = 7 \) → \( x > y \) 4. If \( x = 8 \), then \( y = 9 \) → \( x < y \) From this, we can see that: - When \( x = 5 \), \( y \) can be either \( 7 \) or \( 9 \) (in both cases \( x < y \)). - When \( x = 8 \), \( y \) can be \( 7 \) (in this case \( x > y \)) or \( 9 \) (in this case \( x < y \)). ### Conclusion Since there are instances where \( x < y \) and instances where \( x > y \), we cannot establish a consistent relationship between \( x \) and \( y \). Thus, the answer is: **The relationship cannot be established.**
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