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In the following questions, two equation...

In the following questions, two equations numberded I and II are given. You have to solve both the equations and give answer If:
`I. 22x^2 -x-21=0 II. 22y^2 +43y+21=0`

A

`x lt y`

B

`x ge y`

C

`x gt y`

D

`x le y`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given equations step by step, we will first tackle each equation separately. ### Step 1: Solve Equation I The first equation is: \[ 22x^2 - x - 21 = 0 \] To solve this quadratic equation, we can use the factorization method. We need to find two numbers that multiply to \( 22 \times (-21) = -462 \) and add up to \(-1\) (the coefficient of \(x\)). #### Finding the Factors The factors of \(-462\) that add up to \(-1\) are: - \(21\) and \(-22\) #### Rewriting the Equation We can rewrite the middle term using these factors: \[ 22x^2 + 21x - 22x - 21 = 0 \] #### Grouping Now, group the terms: \[ (22x^2 + 21x) + (-22x - 21) = 0 \] Factor by grouping: \[ 7x(3x + 1) - 21(3x + 1) = 0 \] This gives: \[ (3x + 1)(22x - 21) = 0 \] #### Finding the Roots Setting each factor to zero: 1. \(3x + 1 = 0 \Rightarrow x = -\frac{1}{3}\) 2. \(22x - 21 = 0 \Rightarrow x = \frac{21}{22}\) ### Step 2: Solve Equation II The second equation is: \[ 22y^2 + 43y + 21 = 0 \] Again, we will use the factorization method. We need to find two numbers that multiply to \(22 \times 21 = 462\) and add up to \(43\). #### Finding the Factors The factors of \(462\) that add up to \(43\) are: - \(21\) and \(22\) #### Rewriting the Equation We can rewrite the middle term using these factors: \[ 22y^2 + 21y + 22y + 21 = 0 \] #### Grouping Now, group the terms: \[ (22y^2 + 21y) + (22y + 21) = 0 \] Factor by grouping: \[ y(22y + 21) + 1(22y + 21) = 0 \] This gives: \[ (22y + 21)(y + 1) = 0 \] #### Finding the Roots Setting each factor to zero: 1. \(22y + 21 = 0 \Rightarrow y = -\frac{21}{22}\) 2. \(y + 1 = 0 \Rightarrow y = -1\) ### Step 3: Compare Values of x and y Now we have the values: - From Equation I: \(x = -\frac{1}{3}, \frac{21}{22}\) - From Equation II: \(y = -\frac{21}{22}, -1\) #### Comparing Values 1. **For \(x = -\frac{1}{3}\) and \(y = -\frac{21}{22}\)**: - \(-\frac{1}{3} \approx -0.33\) and \(-\frac{21}{22} \approx -0.95\) - Here, \(x > y\). 2. **For \(x = -\frac{1}{3}\) and \(y = -1\)**: - \(-\frac{1}{3} \approx -0.33\) and \(-1\) - Here, \(x > y\). 3. **For \(x = \frac{21}{22}\) and \(y = -\frac{21}{22}\)**: - \(\frac{21}{22} \approx 0.95\) and \(-\frac{21}{22} \approx -0.95\) - Here, \(x > y\). 4. **For \(x = \frac{21}{22}\) and \(y = -1\)**: - \(\frac{21}{22} \approx 0.95\) and \(-1\) - Here, \(x > y\). ### Conclusion In all cases, we find that \(x\) is greater than \(y\). ### Final Answer Thus, the relation between \(x\) and \(y\) is: \[ x > y \]
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