A jar contains 48 litres of milk and x litres water if new mixture containing 2x l of milk and 3x l of water is added to the jar, the final quantity of this mixture becomes 60 litres. What was the quantity of milk in the final mixture?(in litres)

Options

A. 54
B. 48
C. 52
D. 45

Answer

To solve the problem step by step, we can follow these instructions:

### Step 1: Understand the initial conditions
We know that the jar initially contains:
- 48 liters of milk
- x liters of water

### Step 2: Understand the new mixture being added
The new mixture contains:
- 2x liters of milk
- 3x liters of water

### Step 3: Set up the equation for the final mixture
The total volume of the final mixture is given as 60 liters. Therefore, we can write the equation:
\[ \text{Total Milk} + \text{Total Water} = 60 \]
This can be expressed as:
\[ (48 + 2x) + (x + 3x) = 60 \]

### Step 4: Simplify the equation
Combine the terms in the equation:
\[ 48 + 2x + 4x = 60 \]
This simplifies to:
\[ 48 + 6x = 60 \]

### Step 5: Solve for x
Now, we will isolate x:
\[ 6x = 60 - 48 \]
\[ 6x = 12 \]
\[ x = 2 \]

### Step 6: Calculate the final quantity of milk
Now that we have the value of x, we can find the final quantity of milk in the jar:
\[ \text{Final Milk} = 48 + 2x \]
Substituting the value of x:
\[ \text{Final Milk} = 48 + 2(2) = 48 + 4 = 52 \]

### Final Answer
The quantity of milk in the final mixture is **52 liters**.

---