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A sum of ₹50000 was invested in scheme A...

A sum of ₹50000 was invested in scheme A at `12%` per annum simple interest for three years. A sum of ₹40000 was invested in scheme B at `10%` per annum compound interest compounded annually for 2 years. What is the difference between final amount received from scheme A and that received from scheme B

A

₹19600

B

₹20200

C

₹19000

D

₹19200

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to calculate the final amounts received from both Scheme A and Scheme B, and then find the difference between these amounts. ### Step-by-Step Solution: **Step 1: Calculate Simple Interest for Scheme A** - The formula for Simple Interest (SI) is: \[ \text{SI} = \frac{\text{Principal} \times \text{Rate} \times \text{Time}}{100} \] - For Scheme A: - Principal (P) = ₹50,000 - Rate (R) = 12% - Time (T) = 3 years - Plugging in the values: \[ \text{SI} = \frac{50000 \times 12 \times 3}{100} = \frac{1800000}{100} = ₹18000 \] **Step 2: Calculate Total Amount for Scheme A** - The total amount (A) received from Scheme A is: \[ A = \text{Principal} + \text{Simple Interest} = 50000 + 18000 = ₹68000 \] **Step 3: Calculate Compound Interest for Scheme B** - The formula for Compound Interest (CI) is: \[ A = P \left(1 + \frac{R}{100}\right)^T \] - For Scheme B: - Principal (P) = ₹40,000 - Rate (R) = 10% - Time (T) = 2 years - Plugging in the values: \[ A = 40000 \left(1 + \frac{10}{100}\right)^2 = 40000 \left(1 + 0.1\right)^2 = 40000 \left(1.1\right)^2 \] \[ A = 40000 \times 1.21 = ₹48400 \] **Step 4: Calculate the Difference Between the Two Amounts** - The difference between the amounts received from Scheme A and Scheme B is: \[ \text{Difference} = A_{\text{Scheme A}} - A_{\text{Scheme B}} = 68000 - 48400 = ₹19600 \] ### Final Answer: The difference between the final amount received from Scheme A and that received from Scheme B is **₹19600**. ---
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