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. Aman prints visiting cards of four standard sizes - `(L xx 2)` sq cm, `(6 xx 3)` sq cm, `(5 xx 5)` sq cm and `(2 xx 2)` sq cm. On Monday he printed cards of two sizes `(L xx 2)` sq cm and `(6 xx 3)` sq cm for a client. The respective ratio between the number of `(L xx 2)` sq cm cards and the number of `(6 xx 3)` sq cm cards printed on Monday was 2:3. The client had to pay a total of rs 1600 for the `(L xx 2)` sq cm card and a total of rs 5400 for `(6 xx 3)` sq cm card, (Both at the rate of 2rs per sq. cm).
What is the value of L?

A

3

B

8

C

5

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( L \) given the information about the visiting cards printed by Aman. ### Step-by-Step Solution: 1. **Understand the Sizes and Ratios**: - The sizes of the cards are: - \( (L \times 2) \) sq cm - \( (6 \times 3) \) sq cm - The ratio of the number of \( (L \times 2) \) sq cm cards to \( (6 \times 3) \) sq cm cards printed is \( 2:3 \). 2. **Assume Variables**: - Let the number of \( (L \times 2) \) cards printed be \( 2x \). - Let the number of \( (6 \times 3) \) cards printed be \( 3x \). 3. **Calculate the Area of Each Card**: - Area of \( (L \times 2) \) card = \( 2L \) sq cm. - Area of \( (6 \times 3) \) card = \( 18 \) sq cm (since \( 6 \times 3 = 18 \)). 4. **Calculate the Cost for Each Card**: - Cost of one \( (L \times 2) \) card = \( 2 \times (2L) = 4L \) Rs. - Cost of one \( (6 \times 3) \) card = \( 2 \times 18 = 36 \) Rs. 5. **Total Cost for Each Type of Card**: - Total cost for \( (L \times 2) \) cards = \( 2x \times 4L = 8xL \). - Total cost for \( (6 \times 3) \) cards = \( 3x \times 36 = 108x \). 6. **Set Up the Equations**: - According to the problem, the total cost for \( (L \times 2) \) cards is Rs 1600: \[ 8xL = 1600 \] - The total cost for \( (6 \times 3) \) cards is Rs 5400: \[ 108x = 5400 \] 7. **Solve for \( x \)**: - From \( 108x = 5400 \): \[ x = \frac{5400}{108} = 50 \] 8. **Substitute \( x \) Back to Find \( L \)**: - Substitute \( x = 50 \) into the equation \( 8xL = 1600 \): \[ 8 \times 50 \times L = 1600 \] \[ 400L = 1600 \] \[ L = \frac{1600}{400} = 4 \] ### Final Answer: The value of \( L \) is **4**.
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