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. Aman prints visiting cards of four standard sizes - `(L xx 2)` sq cm, `(6 xx 3)` sq cm, `(5 xx 5)` sq cm and `(2 xx 2)` sq cm. On Monday he printed cards of two sizes `(L xx 2)` sq cm and `(6 xx 3)` sq cm for a client. The respective ratio between the number of `(L xx 2)` sq cm cards and the number of `(6 xx 3)` sq cm cards printed on Monday was 2:3. The client had to pay a total of rs 1600 for the `(L xx 2)` sq cm card and a total of rs 5400 for `(6 xx 3)` sq cm card, (Both at the rate of 2 rs per sq. cm).
Number of cards of `(2xx 2)` sq cm size Aman printed on Wednesday, was 120 more than the number of `(L xx 2)` sq. om cards he printed on Monday. If he charged 8 rs per card on Wednesday to a client, how much did the client pay for all the `(2 xx 2)` sq cm cards printed?

A

Rs... 1720

B

Rs... 1820

C

Rs... 1760

D

Rs... 1480

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the information provided in the question. ### Step 1: Understand the sizes and ratios of the cards printed on Monday Aman printed two sizes of cards on Monday: - Size 1: \( L \times 2 \) sq cm - Size 2: \( 6 \times 3 \) sq cm The ratio of the number of \( L \times 2 \) cards to \( 6 \times 3 \) cards is given as 2:3. Let the number of \( L \times 2 \) cards be \( 2x \) and the number of \( 6 \times 3 \) cards be \( 3x \). ### Step 2: Calculate the area of each card and the total cost for each size 1. **Area of \( L \times 2 \) card**: - Area = \( L \times 2 \) sq cm - Cost per sq cm = Rs 2 - Total cost for \( 2x \) cards = \( 2x \times (L \times 2) \times 2 = 8xL \) 2. **Area of \( 6 \times 3 \) card**: - Area = \( 6 \times 3 = 18 \) sq cm - Total cost for \( 3x \) cards = \( 3x \times 18 \times 2 = 108x \) ### Step 3: Set up equations based on total costs From the problem, we know: - Total cost for \( L \times 2 \) cards = Rs 1600 - Total cost for \( 6 \times 3 \) cards = Rs 5400 Setting up the equations: 1. \( 8xL = 1600 \) 2. \( 108x = 5400 \) ### Step 4: Solve for \( x \) From the second equation: \[ x = \frac{5400}{108} = 50 \] ### Step 5: Substitute \( x \) back to find \( L \) Using \( x = 50 \) in the first equation: \[ 8 \times 50 \times L = 1600 \] \[ 400L = 1600 \implies L = \frac{1600}{400} = 4 \] ### Step 6: Find the number of cards printed on Monday - Number of \( L \times 2 \) cards = \( 2x = 2 \times 50 = 100 \) - Number of \( 6 \times 3 \) cards = \( 3x = 3 \times 50 = 150 \) ### Step 7: Calculate the number of \( 2 \times 2 \) cards printed on Wednesday Aman printed 120 more \( 2 \times 2 \) cards than \( L \times 2 \) cards: \[ \text{Number of } 2 \times 2 \text{ cards} = 100 + 120 = 220 \] ### Step 8: Calculate the total cost for \( 2 \times 2 \) cards Cost per \( 2 \times 2 \) card = Rs 8 Total cost for \( 220 \) cards: \[ \text{Total cost} = 220 \times 8 = 1760 \] ### Final Answer The client paid Rs 1760 for all the \( 2 \times 2 \) cards printed. ---
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