Home
Class 14
MATHS
Directions () : Study the following info...

Directions () : Study the following information carefully and answer the given questions
. Aman prints visiting cards of four standard sizes - `(L xx 2)` sq cm, `(6 xx 3)` sq cm, `(5 xx 5)` sq cm and `(2 xx 2)` sq cm. On Monday he printed cards of two sizes `(L xx 2)` sq cm and `(6 xx 3)` sq cm for a client. The respective ratio between the number of `(L xx 2)` sq cm cards and the number of `(6 xx 3)` sq cm cards printed on Monday was 2:3. The client had to pay a total of rs 1600 for the `(L xx 2)` sq cm card and a total of rs 5400 for `(6 xx 3)` sq cm card, (Both at the rate of 2 rs per sq. cm).
On Friday, Aman printed only `(6 xx 3)` sq cm size cards. The total number of cards printed was 90 more than that printed on Monday at the rate of 5 rs per sq cm. Find the total cost incurred, (in rs)

A

30600

B

31600

C

32500

D

33600

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these calculations: ### Step 1: Understand the sizes and costs of the cards Aman prints visiting cards of four sizes: 1. \( L \times 2 \) sq cm 2. \( 6 \times 3 \) sq cm 3. \( 5 \times 5 \) sq cm 4. \( 2 \times 2 \) sq cm The costs are given at the rate of Rs. 2 per sq cm for the cards printed on Monday. ### Step 2: Calculate the area of each card size - Area of \( L \times 2 \) = \( 2L \) sq cm - Area of \( 6 \times 3 \) = \( 18 \) sq cm - Area of \( 5 \times 5 \) = \( 25 \) sq cm - Area of \( 2 \times 2 \) = \( 4 \) sq cm ### Step 3: Determine the number of cards printed on Monday Let the number of \( L \times 2 \) cards printed be \( 2x \) and the number of \( 6 \times 3 \) cards printed be \( 3x \) (based on the ratio 2:3). ### Step 4: Calculate the total cost for each card type printed on Monday - Total cost for \( L \times 2 \) cards: \[ \text{Cost} = \text{Area} \times \text{Rate} \times \text{Number of cards} = (2L) \times 2 \times (2x) = 8Lx \] - Total cost for \( 6 \times 3 \) cards: \[ \text{Cost} = 18 \times 2 \times (3x) = 108x \] Given that the total cost for \( L \times 2 \) cards is Rs. 1600 and for \( 6 \times 3 \) cards is Rs. 5400, we can set up the equations: 1. \( 8Lx = 1600 \) 2. \( 108x = 5400 \) ### Step 5: Solve for \( x \) From the second equation: \[ x = \frac{5400}{108} = 50 \] ### Step 6: Substitute \( x \) back to find \( L \) From the first equation: \[ 8L(50) = 1600 \implies 400L = 1600 \implies L = 4 \] ### Step 7: Calculate the total number of cards printed on Monday Total cards printed on Monday: \[ 2x + 3x = 5x = 5 \times 50 = 250 \] ### Step 8: Determine the number of cards printed on Friday On Friday, Aman printed 90 more cards than on Monday: \[ \text{Total cards on Friday} = 250 + 90 = 340 \] ### Step 9: Calculate the cost of cards printed on Friday The cards printed on Friday were all \( 6 \times 3 \) cards, with a cost of Rs. 5 per sq cm: \[ \text{Cost of one } 6 \times 3 \text{ card} = 18 \times 5 = 90 \text{ Rs.} \] Total cost for 340 cards: \[ \text{Total Cost} = 340 \times 90 = 30600 \text{ Rs.} \] ### Final Answer The total cost incurred for the cards printed on Friday is Rs. 30,600. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

How many small squares are there in 1sq.cm?

How many small squares are there in 1sq.cm?

The area of the shaded portion is (FIGURE) (a) 10 sq. cm (b) 14 sq. cm (c) 21 sq. cm (d) 25 sq. cm

Areas of two similar triangles are 225 sq cm and 81 sq cm. If a side of the smaller triangle is 12 cm, then find the corresponding side of the bigger triangle.

The area of a side of a box is 120 sq. cm. The area of the other side of the box is 72 sq. cm. If the area of the upper surface of the box is 60 sq. cm. then find the volume of the box ?

The perimeter of a triangle is 16cm. One ofthe sides is of length 6cm .If the area of thetriangle is 12 sq.cm,then the triangle is

The base of a parallelogram is three times its height. If the area of the parallelogram is 75 sq cm, then its height is

If the area of the trapezium whose parallel sides are 6 cm and 10 cm is 32 sq. cm, then the distance between the parallel sides is (a) 2 cm (b) 4 cm (c) 5 cm (d) 8 cm

If the inradius of a triangle with perimeter 32cm is 6cm, then the area of the triangle in sq.cm is