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Shiva took an auto for remaining distanc...

Shiva took an auto for remaining distance of his journey at 25 km/hr he had already travelled a certain distance by walking at 5 km/hr he spent 10 hours for entire journey the average speed is 17km/hr what is distance of journey travelled by auto

A

90km

B

105km

C

135km

D

150km

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to break it down into steps. Here's a step-by-step solution: ### Step 1: Define Variables Let: - \( d_w \) = distance travelled by walking - \( d_a \) = distance travelled by auto - \( t_w \) = time spent walking - \( t_a \) = time spent in auto ### Step 2: Use Given Information From the problem, we know: - Speed while walking = 5 km/hr - Speed while in auto = 25 km/hr - Total time for the journey = 10 hours - Average speed = 17 km/hr ### Step 3: Set Up Equations 1. The total distance \( D \) can be expressed as: \[ D = d_w + d_a \] 2. The total time can be expressed as: \[ t_w + t_a = 10 \] 3. The time spent walking and in the auto can be expressed in terms of distance and speed: \[ t_w = \frac{d_w}{5} \quad \text{and} \quad t_a = \frac{d_a}{25} \] ### Step 4: Substitute Time Equations Substituting \( t_w \) and \( t_a \) into the total time equation: \[ \frac{d_w}{5} + \frac{d_a}{25} = 10 \] ### Step 5: Express \( d_a \) in terms of \( d_w \) To eliminate one variable, we can express \( d_a \) in terms of \( d_w \): \[ \frac{d_a}{25} = 10 - \frac{d_w}{5} \] Multiplying through by 25 to eliminate the fraction: \[ d_a = 250 - 5d_w \] ### Step 6: Substitute into Total Distance Equation Now, substitute \( d_a \) into the total distance equation: \[ D = d_w + (250 - 5d_w) = 250 - 4d_w \] ### Step 7: Use Average Speed The average speed is given by: \[ \text{Average Speed} = \frac{D}{\text{Total Time}} = \frac{250 - 4d_w}{10} = 17 \] ### Step 8: Solve for \( d_w \) Multiply both sides by 10: \[ 250 - 4d_w = 170 \] Rearranging gives: \[ 4d_w = 80 \quad \Rightarrow \quad d_w = 20 \] ### Step 9: Find \( d_a \) Now substitute \( d_w \) back into the equation for \( d_a \): \[ d_a = 250 - 5(20) = 250 - 100 = 150 \] ### Final Answer The distance travelled by auto is: \[ \boxed{150 \text{ km}} \]
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