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Find the wrong number in each of the fo...

Find the wrong number in each of the following number series.
5 6 15 41 105 230 446.

A

105

B

6

C

230

D

15

Text Solution

AI Generated Solution

The correct Answer is:
To find the wrong number in the series 5, 6, 15, 41, 105, 230, 446, we can analyze the pattern of the series step by step. ### Step-by-Step Solution: 1. **Identify the Series**: The given series is: \[ 5, 6, 15, 41, 105, 230, 446 \] 2. **Calculate Differences**: We will find the differences between consecutive terms: - \(6 - 5 = 1\) - \(15 - 6 = 9\) - \(41 - 15 = 26\) - \(105 - 41 = 64\) - \(230 - 105 = 125\) - \(446 - 230 = 216\) So, the differences are: \[ 1, 9, 26, 64, 125, 216 \] 3. **Identify Patterns in Differences**: Now, we will look for a pattern in the differences: - \(1 = 1^3\) - \(9 = 2^3 + 1\) - \(26 = 3^3 - 1\) - \(64 = 4^3\) - \(125 = 5^3\) - \(216 = 6^3\) We can see that the differences are related to cubes of integers, but with some variations. 4. **Check for Consistency**: The expected pattern seems to be: - \(1^3\) - \(2^3 + 1\) - \(3^3 - 1\) - \(4^3\) - \(5^3\) - \(6^3\) However, we notice that the second term (15) does not fit the expected pattern. 5. **Propose a Correction**: If we replace 15 with a number that fits the pattern, we can check: - If we replace 15 with 14, we can check: - \(6 + 8 = 14\) (where \(8 = 2^3\)) - \(14 + 27 = 41\) (where \(27 = 3^3\)) This maintains the pattern of cubes. 6. **Conclusion**: The incorrect number in the series is 15. If we replace it with 14, the series follows the expected pattern. ### Final Answer: The wrong number in the series is **15**.
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