Radius of current carrying coil is 'R.Then ratio of magnetic fields at the centre of the coil to the axial point,which is R `sqrt(3)` distance away from the centre of the coil
(1) 1:1 (2) 1:2 (3) 1:4 (4) 8:1

The magnetic field at the centre of the current carrying coil is

A circular coil of radius 2R is carrying current 'i' . The ratio of magnetic fields at the centre of the coil and at a point at a distance 6R from the centre of the coil on the axis of the coil is

Ratio of magnetic field at the centre of a current carrying coil of radius R and at a distance of 3R on its axis is

The ratio of the magnetic field at the centre of a current carrying coil of the radius a and at distance 'a' from centre of the coil and perpendicular to the axis of coil is

The magnetic field at centre of a hexagonal coil of side l carrying a current I is

The radius of a circular current carrying coil is R. The distance on the axis from the centre of the coil where the intensity of magnetic field is (1)/(2sqrt(2)) times that at the centre, will be:

A circular current carrying coil has a radius R. The distance from the centre of the coil on the axis where the magnetic induction will be (1//8)^(th) of its value at the centre of the coil is,

A circular current carrying coil has a radius R. The distance from the centre of the coil on the axis where the magnetic induction will be (1)/(8) th to its value at the centre of the coil, is

A closely wound, circular coil with radius 2.40 cm has 800 turns. (a) What must the current in the coil be if the magnetic field at the centre of the coil is 0.0580 T ? (b) At what distance x from the centre of the coil, on the axis of the coil, is the magnetic field half its value at the centre?

A conductor of length L and carrying current i is bent to form a coil of two turns.Magnetic field at the centre of the coil will be