Transform to Cartesian coordinate the equations
`r^(1/2) cos (theta)/(2) = a^(1/2)`.

Transform to Cartesian coordinates the equations: r^(2)=a^(2)cos2 theta

Convert Cartesian coordinate into polar coordinate (2,2)

Convert into Cartesian coordinates: ((sqrt2+1)/sqrt2,pi/4)

Solve the following equation: sin^(2)theta-cos theta=(1)/(4)

Transform the equation r = 2 a cos theta to cartesian form.

Solve the following equation: cos^(2)theta-sin theta cos theta-(1)/(2)=0

Among given values of theta which one satisfies the equation (cos theta)/(1- sin theta) -(cos theta)/(1 + sin theta) =2 ?

The solution of the equation 1-"cos" theta = "sin" theta "sin" (theta)/(2) is